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Complete Course of Mathematics
Topic 1: Numbers & Numerical Applications Topic 2: Algebra Topic 3: Quantitative Aptitude
Topic 4: Geometry Topic 5: Construction Topic 6: Coordinate Geometry
Topic 7: Mensuration Topic 8: Trigonometry Topic 9: Sets, Relations & Functions
Topic 10: Calculus Topic 11: Mathematical Reasoning Topic 12: Vectors & Three-Dimensional Geometry
Topic 13: Linear Programming Topic 14: Index Numbers & Time-Based Data Topic 15: Financial Mathematics
Topic 16: Statistics & Probability


Content On This Page
Mensuration: Definition and Scope Perimeter of Plane Figures: Definition and Basic Understanding Area of Plane Figures: Definition and Basic Understanding
Units of Measurement for Perimeter and Area


Introduction to Mensuration: Perimeter and Area Concepts



Mensuration: Definition and Scope

Mensuration is a branch of geometry within mathematics that deals with the measurement of geometric figures. It primarily focuses on calculating lengths, areas, and volumes of various shapes, both two-dimensional (plane figures) and three-dimensional (solid figures).


The term "Mensuration" originates from the Latin word 'mensura', which means 'measure'.


Scope of Mensuration

Mensuration covers a wide range of calculations related to the size and dimensions of shapes and objects. These include:


Importance and Applications of Mensuration

Mensuration is not just an academic topic; it has immense practical importance across numerous fields and in everyday life:

In essence, mensuration provides the foundational quantitative tools to understand and interact with the physical space around us by quantifying the size, extent, and capacity of objects and regions.


Perimeter of Plane Figures: Definition and Basic Understanding

The perimeter of a closed two-dimensional (plane) figure is defined as the total length of its boundary. It represents the distance around the outside edge of the shape. The word "perimeter" comes from the Greek words 'peri' (around) and 'metron' (measure).


Think of it as the length you would measure if you were to trace the outline of the figure with a string and then measure the length of the string.

For example, if you have a picture frame, the perimeter is the total length of the wood or material used for the frame around the picture. If you are putting a decorative border around a tablecloth, the length of the border is the perimeter of the tablecloth.


Key Concepts


Examples

Example 1. A square garden has a side length of $8.5$ metres. A gardener wants to put a fence around it. What is the total length of the fence required?

Answer:

Given:

Side length of the square garden ($s$) $= 8.5$ m.

To Find:

The total length of the fence required, which is the perimeter of the square garden.

Solution:

A square has four equal sides. The perimeter of a square is the sum of the lengths of its four sides. The formula is:

$\text{Perimeter} = s + s + s + s = 4 \times s$

... (i)

Substitute the given side length into the formula:

$\text{Perimeter} = 4 \times 8.5 \$ \text{m}$

[Substitute $s=8.5$ m in (i)]

Now, perform the multiplication:

$\text{Perimeter} = 34.0 \$ \text{m}$

Thus, the total length of the fence required is $34$ metres.


Example 2. Find the perimeter of a rectangle whose length is $25$ cm and width is $18$ cm.

Answer:

Given:

Length of the rectangle ($l$) $= 25$ cm.

Width of the rectangle ($w$) $= 18$ cm.

To Find:

Perimeter of the rectangle.

Solution:

A rectangle has four sides, with opposite sides being equal in length. The perimeter is the sum of the lengths of its two lengths and two widths. The formula for the perimeter of a rectangle is:

$\text{Perimeter} = l + w + l + w = 2l + 2w = 2(l+w)$

... (i)

Substitute the given length and width into the formula:

$\text{Perimeter} = 2 \times (25 \$ \text{cm} + 18 \$ \text{cm})$

[Substitute $l=25$ cm and $w=18$ cm in (i)]

$\text{Perimeter} = 2 \times 43 \$ \text{cm}$

$\text{Perimeter} = 86 \$ \text{cm}$

The perimeter of the rectangle is $86$ cm.


Example 3. A triangular park has sides measuring $200$ m, $150$ m, and $220$ m. Find the perimeter of the park.

Answer:

Given:

Side lengths of the triangular park: $a = 200$ m, $b = 150$ m, $c = 220$ m.

To Find:

Perimeter of the triangular park.

Solution:

The perimeter of any polygon is the sum of the lengths of its sides. For a triangle with side lengths $a$, $b$, and $c$, the perimeter is:

$\text{Perimeter} = a + b + c$

... (i)

Substitute the given side lengths into the formula:

$\text{Perimeter} = 200 \$ \text{m} + 150 \$ \text{m} + 220 \$ \text{m}$

[Substitute values in (i)]

$\text{Perimeter} = (200 + 150 + 220) \$ \text{m}$

$\text{Perimeter} = 570 \$ \text{m}$

The perimeter of the triangular park is $570$ metres.


Example 4. A regular pentagon has a side length of $6$ cm. What is its perimeter?

Answer:

Given:

A regular pentagon with side length ($s$) $= 6$ cm.

To Find:

Perimeter of the regular pentagon.

Solution:

A pentagon is a polygon with $5$ sides. A regular pentagon has $5$ equal sides. The perimeter is the sum of the lengths of its sides.

$\text{Perimeter} = s + s + s + s + s = 5 \times s$

... (i)

Substitute the given side length:

$\text{Perimeter} = 5 \times 6 \$ \text{cm}$

[Substitute $s=6$ cm in (i)]

$\text{Perimeter} = 30 \$ \text{cm}$

The perimeter of the regular pentagon is $30$ cm.


In summary, finding the perimeter of a polygon involves simply adding up the lengths of all its sides. For curved shapes like circles, specific formulas are used, which will be covered in later sections.



Area of Plane Figures: Definition and Basic Understanding

The area of a closed two-dimensional (plane) figure is the measure of the surface or region enclosed within its boundary. It quantifies the amount of space the shape occupies on a flat plane. Area is a fundamental concept in geometry and has numerous practical applications.


Imagine the surface inside the boundary of a figure. The area is the measure of this surface. For example:


Key Concepts


Contrast with Perimeter

It is extremely important not to confuse area and perimeter. While both are measurements related to a closed 2D shape, they quantify different properties:

A key distinction is that two different shapes can have the same perimeter but vastly different areas, and vice versa.


Examples Illustrating Area and its Distinction from Perimeter

Example 1. Find the area of a rectangle with length $10$ cm and width $5$ cm. Also, find its perimeter.

Answer:

Given:

Length of the rectangle ($l$) $= 10$ cm.

Width of the rectangle ($w$) $= 5$ cm.

To Find:

Area and Perimeter of the rectangle.

Solution:

The area of a rectangle is calculated by multiplying its length by its width.

$\text{Area} = \text{Length} \times \text{Width} = l \times w$

... (i)

Substitute the given values:

$\text{Area} = 10 \$ \text{cm} \times 5 \$ \text{cm}$

[Substitute $l=10$ cm, $w=5$ cm in (i)]

$\text{Area} = 50 \$ \text{cm}^2$

The perimeter of a rectangle is calculated as twice the sum of its length and width.

$\text{Perimeter} = 2 \times (\text{Length} + \text{Width}) = 2(l+w)$

... (ii)

Substitute the given values:

$\text{Perimeter} = 2 \times (10 \$ \text{cm} + 5 \$ \text{cm})$

[Substitute $l=10$ cm, $w=5$ cm in (ii)]

$\text{Perimeter} = 2 \times 15 \$ \text{cm}$

$\text{Perimeter} = 30 \$ \text{cm}$

The area of the rectangle is $50 \$ \text{cm}^2$ and its perimeter is $30 \$ \text{cm}$. Note the different units: $\text{cm}^2$ for area and cm for perimeter.


Example 2. Show that two rectangles can have the same perimeter but different areas.

Answer:

Consider two different rectangles:

Rectangle 1:

Length ($l_1$) $= 6$ m

Width ($w_1$) $= 4$ m

Perimeter ($P_1$) $= 2(l_1 + w_1) = 2(6 + 4) = 2(10) = 20$ m

Area ($A_1$) $= l_1 \times w_1 = 6 \times 4 = 24 \$ \text{m}^2$

Rectangle 2:

Length ($l_2$) $= 7$ m

Width ($w_2$) $= 3$ m

Perimeter ($P_2$) $= 2(l_2 + w_2) = 2(7 + 3) = 2(10) = 20$ m

Area ($A_2$) $= l_2 \times w_2 = 7 \times 3 = 21 \$ \text{m}^2$

Observation:

$\text{Perimeter of Rectangle 1} = 20 \$ \text{m}$

$\text{Perimeter of Rectangle 2} = 20 \$ \text{m}$

$\text{Area of Rectangle 1} = 24 \$ \text{m}^2$

$\text{Area of Rectangle 2} = 21 \$ \text{m}^2$

Conclusion:

Both rectangles have the same perimeter ($20$ m), but their areas are different ($24 \$ \text{m}^2$ and $21 \$ \text{m}^2$). This demonstrates that perimeter and area are independent properties of a shape.


Understanding the definition and concept of area, along with its distinction from perimeter and the use of square units, is fundamental before proceeding to the specific formulas for different geometric figures.


Units of Measurement for Perimeter and Area

Choosing the correct units and understanding conversions between them is essential for accurate calculations in mensuration. The unit used must be appropriate for the quantity being measured (length for perimeter, area for surface) and should be consistent within any given problem.


Units for Perimeter (Length)

Perimeter measures linear distance along a boundary. The standard SI unit is the metre (m).

Common units for length include:

Basic Metric Conversions (Length):

Conversions often follow powers of 10:

Unit Symbol Relationship to Metre
Millimetremm$10^{-3}$ m ($0.001$ m)
Centimetrecm$10^{-2}$ m ($0.01$ m)
Decimetredm$10^{-1}$ m ($0.1$ m)
Metrem$1$ m
Decametredam$10^{1}$ m ($10$ m)
Hectometrehm$10^{2}$ m ($100$ m)
Kilometrekm$10^{3}$ m ($1000$ m)

Basic Imperial Conversions (Length):

Metric-Imperial Conversions (Approximate):


Units for Area (Surface)

Area measures the extent of a surface and is expressed in square units. These units are derived by squaring the corresponding linear units.

Common units for area include:

Metric Conversions (Area):

Conversions for area are based on squaring the length conversion factors.

Imperial Conversions (Area):

Metric-Imperial Conversions (Area - Approximate):


Consistency of Units

It is absolutely crucial to use consistent units throughout a calculation. If the dimensions of a figure are given in different units (e.g., length in metres and width in centimetres), you must convert them all to a single unit (either metres or centimetres) before applying any formula for perimeter or area.

Example 1. Find the area of a rectangular tabletop with length $1.5$ m and width $75$ cm.

Answer:

Given:

Length ($l$) $= 1.5$ m.

Width ($w$) $= 75$ cm.

To Find:

Area of the rectangular tabletop.

Solution:

The units for length and width are different (metres and centimetres). We need to convert one of them so that both are in the same unit.

Option 1: Convert to centimetres (cm)

Length ($l$) $= 1.5 \$ \text{m} = 1.5 \times 100 \$ \text{cm} = 150 \$ \text{cm}$

Width ($w$) $= 75 \$ \text{cm}$

Now, calculate the area using the formula $\text{Area} = l \times w$:

$\text{Area} = 150 \$ \text{cm} \times 75 \$ \text{cm}$

$\text{Area} = 11250 \$ \text{cm}^2$

Option 2: Convert to metres (m)

Length ($l$) $= 1.5 \$ \text{m}$

Width ($w$) $= 75 \$ \text{cm} = \frac{75}{100} \$ \text{m} = 0.75 \$ \text{m}$

Now, calculate the area using the formula $\text{Area} = l \times w$:

$\text{Area} = 1.5 \$ \text{m} \times 0.75 \$ \text{m}$

$\text{Area} = 1.125 \$ \text{m}^2$

Both results are correct and equivalent, as $1.125 \$ \text{m}^2 = 1.125 \times 10000 \$ \text{cm}^2 = 11250 \$ \text{cm}^2$. The key is to ensure units are consistent before calculation.


Understanding these units and conversions is vital for solving mensuration problems accurately. Always pay attention to the units given in the problem and the units required for the final answer, performing conversions as necessary.